F(x)=3x^2+4x+3

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Solution for F(x)=3x^2+4x+3 equation: 



(F)=3F^2+4F+3

We move all terms to the left:

(F)-(3F^2+4F+3)=0

We get rid of parentheses

-3F^2+F-4F-3=0

We add all the numbers together, and all the variables

-3F^2-3F-3=0

a = -3; b = -3; c = -3;
Δ = b2-4ac
Δ = -32-4·(-3)·(-3)
Δ = -27
Delta is less than zero, so there is no solution for the equation

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